What is the energy of an emitted flame with a wavelength of #6.5 * 10^-20# m?

2 Answers
Feb 2, 2016

Answer:

#3.058xx10^(-6)j#

Explanation:

we know that,
#E=hf#

#or,E=hc/lambda#[as, #c=flambda#, so, #f=c/lambda#]

#=6.626xx10^(-34)*(3*10^8)/(6.5*10^-20)#[#h#=plunk's constant, #c#= speed of light]

#=3.058xx10^(-6)j#

Feb 2, 2016

Answer:

The wavelength is incredibly short!!! It is difficult to imagine how did they measure it!

Explanation:

Here you have a flame of quite short wavelength well beyond the gamma ray range!!!
If you want, I think, you could use Einstein's equation for the energy #E# of a photon of a certain frequency #nu#:
#E=h*nu#
where:
#k=6.63xx10^-34Js# is Planck's constant;
and also frequecy is related to eavelength #lambda# through the speed of light #c# as:
#c=lambda*nu#
giving an energy of:
#E=6.63xx10^-34*(3xx10^8)/(6.5xx10^-20)=3.06xx10^-6J# and this is for a photon only!!!