# What is the electricity required to produce 1 photon,red photon and blue photon?

Apr 21, 2017

I hope is not too confusing...

#### Explanation:

As an example consider the spectrum:

We can change the wavelength $\lambda$ into frequency $f$ using the speed of light in vacuum $c$:
$c = \lambda f$
so:
Blue light (roughly) ${f}_{B} = \frac{3 \times {10}^{8}}{400 \times {10}^{-} 9} = 7.5 \times {10}^{14} H z$
so we can find the energy needed to get one blue photon as:
$E = h f = 6.63 \times {10}^{-} 34 \cdot 7.5 \times {10}^{14} = 4.97 \times {10}^{-} 19 \approx 5 \times {10}^{-} 19 J$

Now if you have a light generator (hypothetical) you can feed one coulomb carrying this energy and it will produce one blue photon. In terms of current you can produce 1 blue photon each second if you send one of these coulombs of charge each second (representing a current of 1 Ampere).
So summarizing:

The real process of producing a blue photon could be simplified as:

Inside the atom of the filament, the electron that "acquired" energy from the current and jumped to a higher orbital relaxes back emitting the surplus energy in form of a photon of light.