What is the equation for: Hydrochloric acid is added to diammine silver (l) chloride?

2 Answers
Jul 3, 2017

Answer:

#[Ag(NH_3)_2]Cl(aq) + 2HCl(aq) rarr AgCl(s)darr + 2NH_4^+Cl^(-)(aq)#

Explanation:

Silver ion can form a complex ion with ammonia to give #[Ag(NH_3)_2]^+#. The addition of hydrochloric acid would protonate the amine, decompose the complex ion, and cause precipitation of the highly insoluble silver halide as a curdy white precipitate.

Jul 3, 2017

This is kind of an interesting reaction.

From the #"HCl"#, while the #"Cl"^(-)# doesn't really do anything other than induce the common ion effect (the #"Cl"^(-)# on the #"AgCl"(s)# was from the outer coordination sphere of the complex), the #"H"^(+)# can protonate the ammine ligands in the inner coordination sphere:

#["Ag"("NH"_3)_2]"Cl"(aq) + 2"HCl"(aq) -> "AgCl"(s) + 2"NH"_4"Cl"(aq)#

This works since the ammine ligands are Lewis bases. They can break their #sigma# interaction with the #"Ag"# atom (which is fairly weak anyway) and form a stronger #sigma# bond to form the weak acid, #"NH"_4^(+)#.