What is the equation in standard form of the parabola with a focus at (56,44) and a directrix of y= 34?

1 Answer
Feb 23, 2016

#y = 1/(2(b-k))(x-a)^2 + 1/2 (b+k) # where
Point, #F(a,b)# is focus #y = k# is the directrix
#y = 1/20(x^2-112x+2356)#

Explanation:

Without deriving it I claim the equation of a parabola in terms of point of #F(a,b)# and a Directrix, #y = k# is given by:
#y = 1/(2(b-k))(x-a)^2 + 1/2 (b+k) #
In this problem Focus is F(56,44) and Directrix, y = 34
#y = 1/(2(44-34))(x-56)^2 + 1/2 (44+34) #
#y = 1/20(x^2-112x+2356)#