What is the equation of that the tangent line to the curve y = x^1/3 at the point (8, 2)?
1 Answer
May 17, 2018
Explanation:
#"to obtain the equation of the tangent we require slope "#
#"and a point on it"#
#"we have "(x_1,y_1)=(8,2)#
#"the slope m is "dy/dx" at x = 8"#
#y=x^(1/3)#
#rArrdy/dx=1/3x^(-2/3)=1/(3x^(2/3))#
#x=8tody/dx=1/(3xx8^(2/3))=1/12#
#rArry-2=1/12(x-8)#
#rArry-2=1/12x-2/3#
#rArry=1/12x+4/3larrcolor(red)"equation of tangent"#
