Question

What is the equation of the line between `(-3,-3)` and `(-7,1)`?

Answer 1

I found:
`4x+4y+24=0`
or:
`y=-x-6` in Slope-Intercept form.

Explanation:

You can try a relationship such as:
`(x-x_2)/(x_2-x_1)=(y-y_2)/(y_2-y_1)`
Where you use the coordinates of your points `P_1` and `P_2` as:
`(x-(-7))/(-7-(-3))=(y-1)/(1-(-3))`
`(x+7)/(-7+3)=(y-1)/(1+3)`
`(x+7)/-4=(y-1)/4` rearranging:
`4x+28=-4y+4`
so:

`4x+4y+24=0`
or:
`y=-x-6`