What is the equation of the line containing the points (-2, 3) and (1, 2)?

1 Answer
Nov 7, 2017

#y=(-1/3)x+2.3#

Explanation:

First, we find our slope. Slopes are written in #y# over #x# form, or #"rise"/"run"#. You can easily remember this by thinking you would run across the #x# axis, but you would rise along the #y# axis.

Slope can be found with the equation #(y_2-y_1)/(x_2-x_1)# Plug the points given into this formula to find your slope.

#(2-3)/(1-(-2)) rArr -1/3#

Draw a graph using your two points given, then use your newfound slope to continue drawing your slope toward the #y# axis until you intersect it. This point will be your #y#-intercept, or #b# in slope-intercept form.

graph{(-1/3x)+2.3 [-11.27, 14.04, -2.82, 9.84]}

This line looks like it hits the #y# axis at about 2.3, so that is your #b#.

Thus, your answer will be #y=(-1/3)x+2.3#