# What is the equation of the line normal to #f(x)=2x-x^2 # at #x=0#?

##### 1 Answer

Jan 8, 2018

#### Explanation:

I'll start by finding the slope of the line normal to

The line normal to f(x) will be perpendicular to the line tangent to f(x), which will have a slope of f'(x).

Therefore, the slope of the line normal to f(x) will be 1/f'(x)

Based on this the slope of the line normal to f(x) at x = 0, will be

We know that f(x) passes through the point