What is the equation of the line normal to #f(x)=2x-x^2 # at #x=0#?
1 Answer
Jan 8, 2018
Explanation:
I'll start by finding the slope of the line normal to
The line normal to f(x) will be perpendicular to the line tangent to f(x), which will have a slope of f'(x).
Therefore, the slope of the line normal to f(x) will be 1/f'(x)
Based on this the slope of the line normal to f(x) at x = 0, will be
We know that f(x) passes through the point