What is the equation of the line normal to #f(x)=7x ^3+9x^2 # at #x=-2#?

1 Answer
Jul 1, 2016

See explanation

Explanation:

Gradient of the given equation is it differential

Thus #f^'(x)= 21x^2+18x#

#=>f^'(-2)=21(-2)^2+18(-2) = +48#

So the gradient of the line normal to it at this point is:

#y=-1/48x+c#......................................(1)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Let the point on the original curve be #P_1->(x_1,y_1)=(-2,y)#

#f(-2)=y_1=7(-2)^3+9(-2)^2=-20#

#=>P_1->(x_1,y_1)=(-2,-20)#

Substitute these values into equation (1) to find #c#

I will let you do that!