# What is the equation of the line normal to # f(x)=x^2(x-2) # at # x=2#?

##### 1 Answer

Mar 16, 2016

y=

#### Explanation:

First find f'(x) =

At x=2, f(x)=0. Hence the normal at this point (2,0) would be y-0=

On simplification it is y=