# What is the equation of the line normal to # f(x)=xe^(sqrtx)# at # x=1#?

##### 1 Answer

Jan 6, 2017

See the normal-inclusive graph.

#### Explanation:

So, the foot of the normal is P(1, e)..

Both

So, the slope of the normal is the negative reciprocal

And so, the equation to the normal at P(1, e) is

y-e=-3/3e&(-1)(x -1)#.

graph{(y-xe^(sqrtx))(y+0.245x-2.964)=0 [-10, 10, -5, 5]}