Question

What is the equation of the line passing through `(-2,-3)` and `(0,2)`?

Answer 1

`y=(5/2)x +2`

Explanation:

`x_1 = -2, x_2 = 0, y_1 = -3, y_2 = 2`
Plug into slope formula: `(y_2-y_1)/(x_2-x_1)`:

`(2-(-3))/(0-(-2)) = 5/2 = m`

Using one of the points, plug into point slope from, I used `(0,2)`:
`y-2 = (5/2)(x-0)`
Simplify:
`y=(5/2)x+2`

graph{y=(5/2)x+2 [-6.18, 6.24, -3.277, 3.19]}
Both points `(-2,-3)` and `(0,2)` are on the graph