What is the equation of the line passing through #(21,185)# and #(111,-32)#?

1 Answer
Jan 6, 2016

#90y = -217x +21207#

Explanation:

The general formula for a line is #y= mx +c# where #m# is the slope and #c# is the #y# intercept. By substituting the coordinates of the two points given we can solve for #m# and #c#.
#185 = m*21 +c#
#-32 = m*111 +c#
Subtract the second equation form the first and get
#185+32 = 21m -111m#
#217 = -90m#
#m = - 217/90#
Plug this into the first equation to find #c#
#185 = -217/90*21 +c#
#c = (185*90 +217*21)/90#
#c=(16650+4557)/90#
#c = 21207/90#
The equation is therefore #y = -217x/90 +21207/90#
or #90y = -217x +21207#