What is the equation of the line perpendicular to y=-3/7  that passes through  (5,7) ?

The equatarion of the line is $x = 5$
Here The line $y = - \frac{3}{7}$ means the line is parallal to X-axis at a distance $- \frac{3}{7}$ unit from the origin at the direction of Y-axis. Now a line perpendicular to the above line will be parallal to the Y-axis.
Since it passes through the point (5,7), the equatarion of the line is $x = 5$[Answer]