What is the equation of the line perpendicular to #y=3x # that passes through # (-1,28) #?

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Answer 1 · 2016-01-04T10:07:20

3y + x - 83 = 0

y = 3x has a slope m =3

for perpendicular lines # m_1 xx m_2 = -1 #

# 3 xx m_2 = -1 #

# → m_2 = -1/3#

equation of perpendicular line : y - b = m(x - a ) , # m= -1/3 , (a . b ) = (-1 , 28 ) #

substituting in these values gives
# y - 28 = -1/3( x - (-1)) #

multiply through the equation by 3 will eliminate the fraction

so 3y - 84 = - x - 1

hence 3y + x -83 = 0