# What is the equation of the line perpendicular to y=9/5x  that passes through  (-12,8) ?

$y - 8 = - \frac{5}{9} \left(x - - 12\right)$

#### Explanation:

If the line is perpendicular to $y = \frac{9}{5} x$ then we have to use the slope which is negative reciprocal of 9/5.

that is $m = - \frac{1}{\frac{9}{5}} = - \frac{5}{9}$

passing thru the point $\left(- 12 , 8\right)$

Point-Slope Form

$\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

$y - 8 = - \frac{5}{9} \left(x - - 12\right)$

God bless...I hope the explanation is useful..