Question

What is the equation of the line tangent to `f(x)=(x-1)(2x+4)` at `x=0`?

Answer 1

`y=2x-4`

Explanation:

Writing`f(x)=2x^2+2x-4`
so
`f'(x)=4x+2`
`f'(0)=2` and `f(0)=-4`
so we get
`y=2x-4`