Question

What is the equation of the line tangent to `f(x)=xsecx - xcosx` at `x=pi/3`?

Answer 1

`y=(3/2+5*pi/(2*sqrt(3)))*x-5*pi/(6*sqrt(3))`

Explanation:

We get

`f(pi/3)=pi/2`

`f'(x)=-cos(x)+sec(x)+x*sin(x)+x*sec(x)*tan(x)`

`f'(pi/3)=3/2+5*pi/(2*sqrt(3))`