What is the equation of the line that goes through #(4, -1)#, and is parallel to #y=-3/2x+1#?

1 Answer
Feb 24, 2016

#3x+2y=10#

Explanation:

Any line parallel to #y=-3/2x+1# has the same slope i.e. #(-3/2)#

Therefore for any point #(x,y)# through #(4,-1)# parallel to this line:
#color(white)("XXX")(y-(-1))/(x-4)=-3/2#

#color(white)("XXX")2y+2=-3x+12#

#color(white)("XXX")3x+2y=10# (in "standard form")

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