# What is the equation of the line that is normal to #f(x)= (2x-2)/e^(2x-2) # at # x= 1 #?

##### 1 Answer

Feb 10, 2017

#### Explanation:

graph{((2x-2)/(e^(2x-2))-y)(x+2y-1)=0 [-10, 10, -5, 5]}

So, the foot of the normal is P( 1, 0 ).

f'=2e^2(e^(-2x)(x-1)'+(x-1)(e^(-2x))')#

Slope of the normal

So, the equation to the normal is