What is the equation of the line that is normal to #f(x)=-2x^3+4x-2 # at # x=-2 #?
The normal line is perpendicular to the tangent line.
The equation of the normal line is
At x=-2, the y co-ordinate of the point would be
the given point through which the required normal would pass is (-2,6)
Slope of the curve is
The slope of the normal passing through this point would thus be
The point slope form of the required line would be