What is the equation of the line that is normal to #f(x)= ln(x^2-x+1)/x #at # x= 1 #?
Find the y coordinate at x = 1:
The slope, m, of the tangent line is
The slope, n, of the normal line is:
The normal line has a slope of -1 and passes through the point (1, 0). Using the point-slope form of the equation of a line, we obtain the following equation: