# What is the equation of the line that is normal to f(x)= ln(x^2-x) at  x= 1 ?

There is no normal as $f \left(1\right)$ is not defined
$f \left(x\right) = \ln \left({x}^{2} - x\right)$
As, $x \to 1 \implies f \left(1\right) \to - \infty$
Hence, the value of f(x) has a vertical asymptote at $x = 1$, so we could argue that the equation of the tangent as $x \to 1$ is the vertical line $x = 1$, but this would lead to a theoretically infinite number of normals