# What is the equation of the line that is normal to #f(x)= (x-3)^2-2x-2 # at # x=-1 #?

##### 1 Answer

Apr 19, 2017

#### Explanation:

Lets differentiate the function to find the slope of the tangent at

Differentiating the function w.r.t

We find the slope of the tangent at

Slope of the tangent is -6, hence ** slope of the normal is 6** , this because the product of slope of tangent and slope of normal at a point is

Before finding the equation, we need the value of

Now we have the point

The equation of the normal is

On simplification, we get