# What is the equation of the line that is normal to #f(x)=(x+4)^2e^x# at # x=-3 #?

##### 1 Answer

Feb 8, 2017

#### Explanation:

graph{(e^x(x+4)^2-y)(1/3e^3x+y-e^(-3)+e^3)=0 [-4, -2, -0.5, 0.5]}

y > 0.

As

At

So, the foot of the normal is

The slope of the normal is

And so, the equation to the normal at P is