What is the equation of the line that is normal to #f(x)= x-sqrt( 3x+2) # at # x=4 #?
The tangent and normal are orthogonal to each other
Slope of the tangent is 0.599
Slope of the normal is -1/0.599=-1.669
The normal passes through the point (4,0.258)
Equation of the line passing through a point having a slope is given by
Expressing in the standard form ax+by+c=0