Question

What is the equation of the line that passes through `(0,-1)` and is perpendicular to the line that passes through the following points: `(13,20),(16,1)`?

Answer 1

`y= 3/19*x-1`

Explanation:

The slope of the line passes through (13,20) and (16,1) is `m_1=(1-20)/(16-13)=-19/3` We know condition of perpedicularity between two lines is product of their slopes equal to be -1 `:.m_1*m_2=-1 or (-19/3)*m_2=-1 or m_2 = 3/19` So the line passing through (0,-1) is `y+1=3/19*(x-0) or y= 3/19*x-1`graph{3/19*x-1 [-10, 10, -5, 5]} [Ans]