What is the equation of the line that passes through #(5,-1)# and is perpendicular to #y=-x+5#?
We can find the gradient of a perpendicular line by the negative inverse of the first line's gradient. So, as the gradient of the line you are given is -1, the gradient (m) of a line perpendicular to it would be
To find the equation of any line, we can use the formula
Let's sub in our values -
Hope this helped; let me know if I can do anything else:)