# What is the equation of the line that passes through (9,1) and is perpendicular to the line that passes through the following points: (7,-3),(6,3) ?

$y = \frac{1}{6} \cdot x - \frac{1}{2}$
The slope of the line passing through (7,-3) , (6,3) is $\frac{3 + 3}{6 - 7} = - 6$
So the slope of the perpendicular line passing through (9,1) is $\frac{1}{6}$ since the product of slopes of perpendicular lines is -1. Hence the equation of the line passes through (9,1) is $y - 1 = \frac{1}{6} \left(x - 9\right)$or $y = \frac{1}{6} \cdot x - \frac{1}{2}$ {answer]