What is the equation of the line which passes through the points #(2, -3)# and #(1, -3)#?

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Answer 1 · 2018-03-10T22:11:08

#y =-3#

Begin by finding the slope of the line using the formula

#m = (y_2-y_1)/(x_2-x_1)#

For the points
#(2,-3) and (1,-3)#

#x_1 = 2#
#x_2 = -3#
#x_2 = 1#
#y_2=-3#

#m = (-3-(-3))/(1-2)#

#m=0/-1#

#m=0#

This equation is actually a horizontal line running through the y axis at #y=-3#