What is the equation of the normal line of #f(x)=-2x^3+x^2-2x-1# at #x=-2#?
First find the slope of the tangent line at the given point. It would be f' (-2).
The slope of the normal would be
At x=-2, f(x) would be 16+4+4-1 =23. The given point is this (-2, 23)
Equation of the normal line, in point slope form would be