What is the equation of the normal line of #f(x)=sqrt(x^2-x)# at #x=2#?
The normal line will be perpendicular to the tangent line when
We can determine what point on
If we already have a point on the normal line, all we need to know is its slope. We can find of the tangent line when
Find the slope of the tangent line.
Take the opposite reciprocal to find that the slope of the normal line is
Write the equation in point-slope form:
In slope-intercept form: