# What is the equation of the normal line of #f(x)=x^3-4x^2+7x# at #x=-2#?

##### 1 Answer

Apr 2, 2016

#### Explanation:

From the given equation

We need the negative reciprocal of slope m and the point

Solve for the slope m

Solve for

Our needed point

Let us now solve for the normal line

#y=-1/35(x+2)-38

Kindly see the graph of

graph{(y+1/35x+1332/35)(y-x^3+4x^2-7x)=0[-90,90,-45,45]}

God bless....I hope the explanation is useful.