# What is the equation of the normal line of #f(x)=x/sqrt(x+1/x)# at #x=2 #?

##### 1 Answer

Jan 21, 2017

#### Explanation:

The slope of the normal is -1 / f'=--16.58, nearly.

So, the equation to the normal at P(2, 1.265) is

graph{(y-x/sqrt(x+1/x))(y+16.6x-34.4)((x-2)^2+(y-1.3)^2-.01)=0 [-10, 10, -5, 5]}