What is the equation of the parabola that has a vertex at (-12, -11) and passes through point (-9,16) ?
1 Answer
Jun 17, 2018
Explanation:
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
"here "(h,k)=(-12,-11)
y=a(x+12)^2-11
"to find a substitute "(-9,16)" into the equation"
16=9a-11rArr9a=27rArra=3
y=3(x+12)^2-11larrcolor(red)"in vertex form"
"distribute and rearrange"
y=3(x^2+24x+144)-11
color(white)(y)=3x^2+72x+421larrcolor(red)"in standard form"