What is the equation of the parabola that has a vertex at (-12, -11) and passes through point (-9,16) ?

1 Answer
Jun 17, 2018

y=3x^2+72x+421

Explanation:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))

"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"

"here "(h,k)=(-12,-11)

y=a(x+12)^2-11

"to find a substitute "(-9,16)" into the equation"

16=9a-11rArr9a=27rArra=3

y=3(x+12)^2-11larrcolor(red)"in vertex form"

"distribute and rearrange"

y=3(x^2+24x+144)-11

color(white)(y)=3x^2+72x+421larrcolor(red)"in standard form"