Question

What is the equation of the parabola that has a vertex at `(-4, 5)` and passes through point `(-8,-40)`?

Answer 1

The equation of parabola is `y=-45/16(x+4)^2+5`

Explanation:

The equation of parabola whose vertex is at (-4,5) is `y=a(x+4)^2+5` Since the point (-8,-40) is on the parabola then `-40=a( -8+4)^2+5 or 16a = -45 or a = - 45/16` Hence the equation is `y=-45/16(x+4)^2+5` graph{-45/16(x+4)^2+5 [-20, 20, -10, 10]} [ans]