What is the equation of the parabola that has a vertex at # (42, 7) # and passes through point # (37,32) #?
1 Answer
Jan 24, 2016
# y = ( x - 42 )^2 + 7#
Explanation:
The vertex form of the quadratic function is :
# y = a ( x - h )^2 + k # where (h , k ) are the coordinates of the vertex .
hence equation can be written as :
# y = a (x - 42 )^2 + 7 # Substitute ( 37 ,32 ) into equation to find a.
ie
# a ( 37 - 42 )^2 + 7 = 32 rArr 25a + 7 = 32 # so 25a = 32 - 7 = 25 and a = 1
equation is therefore :
