Question

What is the equation of the tangent line of `f(x)=1/x-1/x^2+x^3` at `x=1`?

Answer 1

y-1=4(x-1)

Explanation:

Slope would be f '(x)=`-1/x^2 +2/x^3 +3x^2` which gives f ' (1)= 4

At x=1, f(1) =1.

Hence equation of tangent line would be (in point slope form) y-1=4(x-1)