Question

What is the equation of the tangent line of `f(x)=(2x)/(x+1)^2` at `x=0`?

Answer 1

The tangent is `y=2x`

Explanation:

The equation of the tangent at `x=0` is

`y-f(0)=f'(0)*(x-0)=`

where `f(0)=0` and `f'(0)=2`

hence `y=2x`