Question

What is the equation of the tangent line of `f(x) =(e^x-x)(e^x-x^2)` at `x=4`?

Answer 1

`y_T=(48-29e^4+2e^8)x-128+96e^4-7e^8`

Explanation:

`f'(x)=2e^(2x)-e^x-3xe^x-e^xx^2+3x^2`
`f'(4)=48-29e^4+2e^8`
`f(4)=(-16+e^4)(e^4-4)`