What is the equation of the tangent line of #f(x) =tan^2x*sec2x-e^xcosx# at #x=pi/4#? Calculus Derivatives Tangent Line to a Curve 1 Answer Lovecraft Nov 11, 2015 We have #y = tan^2(x)sec(2x) - e^(x)cos(x)# However at #pi/4#, #sec(2x)# is not defined, so the function as whole is not defined and therefore there is no tangent line at that point. Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1584 views around the world You can reuse this answer Creative Commons License