What is the equation of the tangent line of $f(x) =tan^2x*sec2x-e^xcosx$ at $x=pi/4$ ?

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Answer 1 · 2015-11-11T22:23:49

We have

$y = tan^2(x)sec(2x) - e^(x)cos(x)$

However at $pi/4$ , $sec(2x)$ is not defined, so the function as whole is not defined and therefore there is no tangent line at that point.

What is the equation of the tangent line of f(x) =tan^2x*sec2x-e^xcosxf(x) =tan^2x*sec2x-e^xcosx at x=pi/4x=pi/4?