Question

What is the equation of the tangent line(s) of `f(x) =x^3-(x^2-4)/(x-4)` at `x=0`?

Answer 1

`y=-x/4-1`

Explanation:

`f(0)=-1`

`f' (0) = -1/4` the slope

the point `(0, -1`

`y-y_1=m(x-x_1)`

`y-(-1)=-1/4*(x-0)`

`y=-x/4-1`