What is the factorization of #4x^2+6x+2#?

1 Answer
Nghi N.
Aug 4, 2016

2(x + 1)(2x + 1)

Explanation:

#y = 2(2x^2 + 3x + 1)#
Factor the trinomial in parentheses.
Since a - b + c = 0, use shortcut. One real root is -1 and the factor is (x + 1). The other root is: #-c/a = -1/2# and the factor is #(x + 1/2)#
Factor form of y:
y = 2(x + 1)(2x + 1)

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