Question

What is the force exerted by the atmosphere on a pool of water that is 30 m long and 10 m wide, the the atmospheric pressure is 100 K Pa ?

Answer 1

`"The force is "3*10^7 N`

Explanation:

Pressure is force divided by area. The Pascal is the S.I. for pressure and is equivalent to the combination of units `N/m^2`. So `100 K Pa = 1*10^5 N/m^2`

Since pressure = force / by area, we need the area of the surface of that pool.

#"area = lengthwidth = 30 m10 m = 300 m^2

Since `pressure = "force" / "area"`,

`"force" = pressure*area`
`"force" = 1*10^5 N/cancel(m^2)*300 cancel(m^2)`
`"force" = 300*10^5 N = 3*10^7 N`

That is 3,000,000 N!

I hope this helps,
Steve