Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `-5 C` and `-7 C` that are `3 m` apart?

Answer 1

`3.89k` `N`

Explanation:

Electrostatic force of repulsion between two like charges of `q_1` and `q_2` separated by a distance of `r` is given as,

`F=(kq_1 q_2)/r^2` where, `k` is a constant

Now,here, given that `q_1=-5C,q_2=-7C,r=3m`

So putting the values we get,

`F=(-5×-7k)/3^2=3.89k` `N`