# What is the force, in terms of Coulomb's constant, between two electrical charges of -2 C and 4 C that are 6 m  apart?

Feb 20, 2017

The force would be attractive, and equal in magnitude to $\frac{2 k}{9} N$

#### Explanation:

If we write the constant part of Coulomb's law as $k$, the formula states

${F}_{E} = \frac{k {Q}_{1} {Q}_{2}}{r} ^ 2$

With the values given in this question, the force becomes

${F}_{E} = \frac{k \left(- 2\right) \left(4\right)}{6} ^ 2 = \frac{k \left(- 8\right)}{36} = \frac{- 2 k}{9} N$

The negative sign tells us the force is attractive.