What is the force, in terms of Coulomb's constant, between two electrical charges of $-2 C$ and $4 C$ that are $6 m$ apart?

Question

1332 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-20T20:07:08

The force would be attractive, and equal in magnitude to $(2k)/9 N$

If we write the constant part of Coulomb's law as $k$ , the formula states

$F_E=(kQ_1Q_2)/r^2$

With the values given in this question, the force becomes

$F_E=(k(-2)(4))/6^2 = (k(-8))/36 = (-2k)/9 N$

The negative sign tells us the force is attractive.

What is the force, in terms of Coulomb's constant, between two electrical charges of -2 C-2 C and 4 C4 C that are 6 m 6 m apart?