# What is the force, in terms of Coulomb's constant, between two electrical charges of 7 C and -3 C that are 6 m  apart?

Apr 6, 2018

I get $\left(- 7 \setminus {\text{C"^2*k)/(12 \ "m}}^{2}\right)$.

#### Explanation:

We use Coulomb's law, which states that,

$F = k \frac{{q}_{1} {q}_{2}}{r} ^ 2$

• ${q}_{1} , {q}_{2}$ are the two electrical charges

• $r$ is the distance between the charges in meters

And so, the force in terms of the constant will be,

$F = k \cdot {\left(7 \setminus \text{C"*-3 \ "C")/(6 \ "m}\right)}^{2}$

$= \left(- 21 \setminus {\text{C"^2*k)/(36 \ "m}}^{2}\right)$

$= \left(- 7 \setminus {\text{C"^2*k)/(12 \ "m}}^{2}\right)$