What is the force, in terms of Coulomb's constant, between two electrical charges of #7 C# and #-3 C# that are #6 m # apart?

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Answer 1 · 2018-04-06T11:29:55

I get #(-7 \ "C"^2*k)/(12 \ "m"^2)#.

We use Coulomb's law, which states that,

#F=k(q_1q_2)/r^2#

#q_1,q_2# are the two electrical charges

#r# is the distance between the charges in meters

And so, the force in terms of the constant will be,

#F=k*(7 \ "C"*-3 \ "C")/(6 \ "m")^2#

#=(-21 \ "C"^2*k)/(36 \ "m"^2)#

#=(-7 \ "C"^2*k)/(12 \ "m"^2)#