What is the force, in terms of Coulomb's constant, between two electrical charges of 22 C and -3 C that are 6 m  apart?

Mar 4, 2017

$| F | \approx 1.6 \cdot {10}^{10} N$

Explanation:

The force between two charges is given by Coulomb's Law:

$| F | = k \frac{| {q}_{1} | | {q}_{2} |}{r} ^ 2$

Where $k$ is a constant equal to $8.99 \cdot {10}^{9} \frac{N \cdot {m}^{2}}{C} ^ 2$

We are given that $r = 6.0 m , {q}_{1} = 22 C ,$ and ${q}_{2} = - 3 C$.

$\implies | F | = \left(8.99 \cdot {10}^{9} \frac{N \cdot {m}^{2}}{C} ^ 2\right) \frac{\left(22 C\right) \left(3 C\right)}{6.0 m} ^ 2$

$\approx 1.6 \cdot {10}^{10} N$