Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `22 C` and `-32 C` that are `7 m` apart?

Answer 1

`~~-14.37 \ "C"^2"/m"^2*k`

Explanation:

Coulomb's law states that:

`F=k(q_1q_2)/r^2`

where:

• `F` is the force experienced in newtons

• `k` is Coulomb's constant

• `q_1,q_2` are the charges of the two charges in coulombs

• `r` is the distance between the two charges in meters

So, we get:

`F=k*(22 \ "C"*-32 \ "C")/(7 \ "m")^2`

`=k*(-704 \ "C"^2)/(49 \ "m"^2)`

`~~-14.37 \ "C"^2"/m"^2*k`