# What is the force, in terms of Coulomb's constant, between two electrical charges of 22 C and -32 C that are 7 m  apart?

Jun 21, 2018

$\approx - 14.37 \setminus {\text{C"^2"/m}}^{2} \cdot k$

#### Explanation:

Coulomb's law states that:

$F = k \frac{{q}_{1} {q}_{2}}{r} ^ 2$

where:

• $F$ is the force experienced in newtons

• $k$ is Coulomb's constant

• ${q}_{1} , {q}_{2}$ are the charges of the two charges in coulombs

• $r$ is the distance between the two charges in meters

So, we get:

$F = k \cdot {\left(22 \setminus \text{C"*-32 \ "C")/(7 \ "m}\right)}^{2}$

$= k \cdot \left(- 704 \setminus {\text{C"^2)/(49 \ "m}}^{2}\right)$

$\approx - 14.37 \setminus {\text{C"^2"/m}}^{2} \cdot k$