What is the force, in terms of Coulomb's constant, between two electrical charges of $16 C$ and $-2 C$ that are $9 m$ apart?

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Answer 1 · 2018-05-01T18:20:30

$=>F = 3.55 xx 10^9 " N"$

or

$=>F = 0.395 k " N"$

Coulomb's Law states that the force between two charges $q_1$ and $q_2$ separated by distance $r$ is:

$=>F = k (|q_1||q_2|)/r^2$

where $k = 8.99 xx 10^9 ("N" * "m") / "C"^2$

Hence,

$F = (8.99 xx 10^9) (|16||-2|)/(9)^2$

$F = (8.99 xx 10^9)(0.39506)$

$=>F = 3.55 xx 10^9 " N"$

If you do want this only in terms of the constant, then this problem is simpler.

$=>F = 0.395 k$

What is the force, in terms of Coulomb's constant, between two electrical charges of 16 C16 C and -2 C-2 C that are 9 m 9 m apart?